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How many chords can be drawn in a circle?

Number of chords that can be formed using the 21 points =21×20×19! 2×1×19! Therefore, the number of chords that can be formed using the 21 points lying on the circle is 210 chords.

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Hint:

Here, we will use the concept of chord of a circle. A chord is defined as a line segment formed by joining any two distinct points lying on the circle. It is formed by joining any 2 of the 21 points lying on the circle. We will use the formula for combinations to find the required number of chords. Formula Used: The number of ways in which the [n] objects can be placed in [r] spaces, where order of objects is not important, can be found using the formula for combinations [{}^n{C_r} = dfrac{{n!}}{{r!left( {n - r} ight)!}}].

Complete step by step solution:

We will use combinations to find the number of chords that we can draw through 21 points on a circle. The number of ways in which the [n] objects can be placed in [r] spaces, where order of objects is not important, can be found using the formula for combinations [{}^n{C_r} = dfrac{{n!}}{{r!left( {n - r} ight)!}}]. The number of chords that can be formed using the 21 points, taking 2 points at a time, is given by [{}^{21}{C_2}]. Substituting [n = 21] and [r = 2] in the formula for combinations, we get Number of chords that can be formed using the 21 points [ = {}^{21}{C_2} = dfrac{{21!}}{{2!left( {21 - 2} ight)!}}] We know that [n!] can be written as [nleft( {n - 1} ight)!] or [nleft( {n - 1} ight)left( {n - 2} ight)!]. Rewriting [21!] as [21left( {21 - 1} ight)left( {21 - 2} ight)!], we get [ Rightarrow ]Number of chords that can be formed using the 21 points [ = {}^{21}{C_2} = dfrac{{21left( {21 - 1} ight)left( {21 - 2} ight)!}}{{2!left( {21 - 2} ight)!}}]

Simplifying the expression, we get

[ Rightarrow ]Number of chords that can be formed using the 21 points [ = dfrac{{21 imes 20 imes 19!}}{{2 imes 1 imes 19!}}]

Therefore, we get

[ Rightarrow ]Number of chords that can be formed using the 21 points [ = 21 imes 10]

Multiplying 21 by 10, we get

[ Rightarrow ] Number of chords that can be formed using the 21 points [ = 210] Therefore, the number of chords that can be formed using the 21 points lying on the circle is 210 chords.

Note:

We used combinations instead of permutations to find the number of chords that can be formed using the points on the circle. A chord is formed using 2 points. Suppose two of the 21 points are A and B. Now, if A is joined to B, the chord is AB. If B is joined to A, the chord is BA. However, BA and AB are the same. If we used permutations, the chords AB and BA will be counted as 2 different chords. Therefore, we have used combinations since it does not matter which point is the initial points and which point is the terminal point.

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What are open chords on piano?

An open chord is when the notes of the chord are spread out so that there is a space in between the notes of the chord.

Triad Chords

In this video we are going to learn how to play piano major open chords and how to properly distribute the notes between hands. Open chords voicing is used for orchestral, strings and pad arrangements since open chords produce a colorful sound and provide a wider space separation between the instruments. Open chords are also very useful when playing chord melody since it gives more space to the melody line.

The C Major Chord – Close Disposition

A close chord is when the notes of the chord are close together so no other note of the chord can be fit in between.

The C Major Open Chord

An open chord is when the notes of the chord are spread out so that there is a space in between the notes of the chord.

Major Open Chord on Root Position

To create an open chord, we move the middle note of the chord 1 octave up. On root position, the middle note of the chord is the 3rd (in this case E).

Major Open Chord on 1st Inversion

For 1st inversion, the middle note is the perfect 5th (on this case G) to make the open chord we play it 1 octave up.

Major Open Chord on 2nd Inversion

For the 2nd inversion, the middle note is the root (in this case C)

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