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Do sets automatically remove duplicates?

Set does not allow duplicates and sets like LinkedHashSet maintains the order of insertion so it will remove duplicates and elements will be printed in the same order in which it is inserted. Convert the formed set into array.

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Given an unsorted array of integers, print the array after removing the duplicate elements from it. We need to print distinct array elements according to their first occurrence.

Examples:

Input: arr[] = { 1, 2, 5, 1, 7, 2, 4, 2} Output: 1 2 5 7 4 Explanation: {1, 2} appear more than one time. Input: arr[] = { 3, 3, 4, 1, 1} Output: 3 4 1

Approach:

Take a Set

Insert all array element in the Set. Set does not allow duplicates and sets like LinkedHashSet maintains the order of insertion so it will remove duplicates and elements will be printed in the same order in which it is inserted.

Convert the formed set into array.

Print elements of Set.

Below is the implementation of the above approach:

C++

#include using namespace std; void removeDuplicates( int arr[], int n) { unordered_set< int > s; for ( int i = 0; i < n; i++) s.insert(arr[i]); cout << "[ " ; for ( auto x : s) cout << x << " " ; cout << "]" ; } int main() { int arr[] = { 1, 2, 5, 1, 7, 2, 4, 2 }; int n = sizeof (arr) / sizeof (arr[0]); removeDuplicates(arr, n); } Java import java.util.*; class GFG { public static void removeDuplicates( int [] arr) { LinkedHashSet set = new LinkedHashSet(); for ( int i = 0 ; i < arr.length; i++) set.add(arr[i]); System.out.print(set); } public static void main(String[] args) { int arr[] = { 1 , 2 , 5 , 1 , 7 , 2 , 4 , 2 }; removeDuplicates(arr); } } Python3 def removeDulipcates(arr): return list ( set (arr)) arr = [ 1 , 2 , 5 , 1 , 7 , 2 , 4 , 2 ] print (removeDulipcates(arr)) C# using System; using System.Collections.Generic; class GFG { public static void removeDuplicates( int [] arr) { HashSet< int > set = new HashSet< int >(); for ( int i = 0; i < arr.Length; i++) set .Add(arr[i]); foreach ( int item in set ) Console.Write(item + ", " ); } public static void Main(String[] args) { int [] arr = { 1, 2, 5, 1, 7, 2, 4, 2 }; removeDuplicates(arr); } } Javascript

Output [ 4 7 5 1 2 ]

Time Complexity: O(N)

Auxiliary Space: O(N) as using unordered_set

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"Zoe'" is the anglicized variant of the word zo, Haitian Creole for "bone", as members were known to be "hard to the bone." When conflicts against Haitians arose, the pound would be sought out to retaliate; thus, the street gang name, "Zoe Pound", was born.

en.wikipedia.org - Zoe Pound - Wikipedia

Street gang founded in Miami, Florida, US

Zoe Pound is a criminal street gang based in Miami, Florida founded by Haitian immigrants in the mid-1990s.[1]

Etymology [ edit ]

"Zoe'" is the anglicized variant of the word zo, Haitian Creole for "bone", as members were known to be "hard to the bone." When conflicts against Haitians arose, the pound would be sought out to retaliate; thus, the street gang name, "Zoe Pound", was born.[4] "Pound" may also stand for "Power Of (the) Unified Negroes (in) Divinity".[5]

History [ edit ]

Having branched out from Miami in the two decades leading up to 2010, they are known to be involved in drug trafficking and robbery and related violent crimes in support of their drug trafficking activities in Evansville, Indiana.[1] In 2004, six Zoe Pound leaders were arrested on racketeering and conspiracy charges in Fort Pierce, Florida after Florida Department of Law Enforcement offices convinced several gang members to give testimony for the prosecution.[3]

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